Optimal. Leaf size=153 \[ \frac {1}{2} f^2 \log \left (-\frac {e x^2}{d}\right ) \log \left (c \left (d+e x^2\right )^p\right )+\frac {f g \left (d+e x^2\right ) \log \left (c \left (d+e x^2\right )^p\right )}{e}+\frac {1}{4} g^2 x^4 \log \left (c \left (d+e x^2\right )^p\right )-\frac {d^2 g^2 p \log \left (d+e x^2\right )}{4 e^2}+\frac {1}{2} f^2 p \text {Li}_2\left (\frac {e x^2}{d}+1\right )+\frac {d g^2 p x^2}{4 e}-f g p x^2-\frac {1}{8} g^2 p x^4 \]
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Rubi [A] time = 0.20, antiderivative size = 153, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 8, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.320, Rules used = {2475, 43, 2416, 2389, 2295, 2394, 2315, 2395} \[ \frac {1}{2} f^2 p \text {PolyLog}\left (2,\frac {e x^2}{d}+1\right )+\frac {1}{2} f^2 \log \left (-\frac {e x^2}{d}\right ) \log \left (c \left (d+e x^2\right )^p\right )+\frac {f g \left (d+e x^2\right ) \log \left (c \left (d+e x^2\right )^p\right )}{e}+\frac {1}{4} g^2 x^4 \log \left (c \left (d+e x^2\right )^p\right )-\frac {d^2 g^2 p \log \left (d+e x^2\right )}{4 e^2}+\frac {d g^2 p x^2}{4 e}-f g p x^2-\frac {1}{8} g^2 p x^4 \]
Antiderivative was successfully verified.
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Rule 43
Rule 2295
Rule 2315
Rule 2389
Rule 2394
Rule 2395
Rule 2416
Rule 2475
Rubi steps
\begin {align*} \int \frac {\left (f+g x^2\right )^2 \log \left (c \left (d+e x^2\right )^p\right )}{x} \, dx &=\frac {1}{2} \operatorname {Subst}\left (\int \frac {(f+g x)^2 \log \left (c (d+e x)^p\right )}{x} \, dx,x,x^2\right )\\ &=\frac {1}{2} \operatorname {Subst}\left (\int \left (2 f g \log \left (c (d+e x)^p\right )+\frac {f^2 \log \left (c (d+e x)^p\right )}{x}+g^2 x \log \left (c (d+e x)^p\right )\right ) \, dx,x,x^2\right )\\ &=\frac {1}{2} f^2 \operatorname {Subst}\left (\int \frac {\log \left (c (d+e x)^p\right )}{x} \, dx,x,x^2\right )+(f g) \operatorname {Subst}\left (\int \log \left (c (d+e x)^p\right ) \, dx,x,x^2\right )+\frac {1}{2} g^2 \operatorname {Subst}\left (\int x \log \left (c (d+e x)^p\right ) \, dx,x,x^2\right )\\ &=\frac {1}{4} g^2 x^4 \log \left (c \left (d+e x^2\right )^p\right )+\frac {1}{2} f^2 \log \left (-\frac {e x^2}{d}\right ) \log \left (c \left (d+e x^2\right )^p\right )+\frac {(f g) \operatorname {Subst}\left (\int \log \left (c x^p\right ) \, dx,x,d+e x^2\right )}{e}-\frac {1}{2} \left (e f^2 p\right ) \operatorname {Subst}\left (\int \frac {\log \left (-\frac {e x}{d}\right )}{d+e x} \, dx,x,x^2\right )-\frac {1}{4} \left (e g^2 p\right ) \operatorname {Subst}\left (\int \frac {x^2}{d+e x} \, dx,x,x^2\right )\\ &=-f g p x^2+\frac {1}{4} g^2 x^4 \log \left (c \left (d+e x^2\right )^p\right )+\frac {f g \left (d+e x^2\right ) \log \left (c \left (d+e x^2\right )^p\right )}{e}+\frac {1}{2} f^2 \log \left (-\frac {e x^2}{d}\right ) \log \left (c \left (d+e x^2\right )^p\right )+\frac {1}{2} f^2 p \text {Li}_2\left (1+\frac {e x^2}{d}\right )-\frac {1}{4} \left (e g^2 p\right ) \operatorname {Subst}\left (\int \left (-\frac {d}{e^2}+\frac {x}{e}+\frac {d^2}{e^2 (d+e x)}\right ) \, dx,x,x^2\right )\\ &=-f g p x^2+\frac {d g^2 p x^2}{4 e}-\frac {1}{8} g^2 p x^4-\frac {d^2 g^2 p \log \left (d+e x^2\right )}{4 e^2}+\frac {1}{4} g^2 x^4 \log \left (c \left (d+e x^2\right )^p\right )+\frac {f g \left (d+e x^2\right ) \log \left (c \left (d+e x^2\right )^p\right )}{e}+\frac {1}{2} f^2 \log \left (-\frac {e x^2}{d}\right ) \log \left (c \left (d+e x^2\right )^p\right )+\frac {1}{2} f^2 p \text {Li}_2\left (1+\frac {e x^2}{d}\right )\\ \end {align*}
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Mathematica [A] time = 0.09, size = 121, normalized size = 0.79 \[ \frac {2 e \log \left (c \left (d+e x^2\right )^p\right ) \left (2 e f^2 \log \left (-\frac {e x^2}{d}\right )+g \left (4 d f+4 e f x^2+e g x^4\right )\right )-2 d^2 g^2 p \log \left (d+e x^2\right )+4 e^2 f^2 p \text {Li}_2\left (\frac {e x^2}{d}+1\right )-e g p x^2 \left (-2 d g+8 e f+e g x^2\right )}{8 e^2} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.68, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (g^{2} x^{4} + 2 \, f g x^{2} + f^{2}\right )} \log \left ({\left (e x^{2} + d\right )}^{p} c\right )}{x}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (g x^{2} + f\right )}^{2} \log \left ({\left (e x^{2} + d\right )}^{p} c\right )}{x}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 0.30, size = 652, normalized size = 4.26 \[ -\frac {i \pi \,g^{2} x^{4} \mathrm {csgn}\left (i c \left (e \,x^{2}+d \right )^{p}\right )^{3}}{8}-\frac {i \pi \,f^{2} \mathrm {csgn}\left (i c \left (e \,x^{2}+d \right )^{p}\right )^{3} \ln \relax (x )}{2}+\frac {g^{2} x^{4} \ln \relax (c )}{4}+\frac {d f g p \ln \left (e \,x^{2}+d \right )}{e}+\frac {g^{2} x^{4} \ln \left (\left (e \,x^{2}+d \right )^{p}\right )}{4}+f^{2} \ln \relax (x ) \ln \left (\left (e \,x^{2}+d \right )^{p}\right )-f^{2} p \dilog \left (\frac {-e x +\sqrt {-d e}}{\sqrt {-d e}}\right )-f^{2} p \dilog \left (\frac {e x +\sqrt {-d e}}{\sqrt {-d e}}\right )-\frac {g^{2} p \,x^{4}}{8}-f g p \,x^{2}+f g \,x^{2} \ln \left (\left (e \,x^{2}+d \right )^{p}\right )+f^{2} \ln \relax (c ) \ln \relax (x )+f g \,x^{2} \ln \relax (c )-f^{2} p \ln \relax (x ) \ln \left (\frac {-e x +\sqrt {-d e}}{\sqrt {-d e}}\right )-f^{2} p \ln \relax (x ) \ln \left (\frac {e x +\sqrt {-d e}}{\sqrt {-d e}}\right )-\frac {i \pi f g \,x^{2} \mathrm {csgn}\left (i c \right ) \mathrm {csgn}\left (i \left (e \,x^{2}+d \right )^{p}\right ) \mathrm {csgn}\left (i c \left (e \,x^{2}+d \right )^{p}\right )}{2}-\frac {i \pi \,g^{2} x^{4} \mathrm {csgn}\left (i c \right ) \mathrm {csgn}\left (i \left (e \,x^{2}+d \right )^{p}\right ) \mathrm {csgn}\left (i c \left (e \,x^{2}+d \right )^{p}\right )}{8}+\frac {i \pi f g \,x^{2} \mathrm {csgn}\left (i c \right ) \mathrm {csgn}\left (i c \left (e \,x^{2}+d \right )^{p}\right )^{2}}{2}+\frac {i \pi f g \,x^{2} \mathrm {csgn}\left (i \left (e \,x^{2}+d \right )^{p}\right ) \mathrm {csgn}\left (i c \left (e \,x^{2}+d \right )^{p}\right )^{2}}{2}-\frac {i \pi \,f^{2} \mathrm {csgn}\left (i c \right ) \mathrm {csgn}\left (i \left (e \,x^{2}+d \right )^{p}\right ) \mathrm {csgn}\left (i c \left (e \,x^{2}+d \right )^{p}\right ) \ln \relax (x )}{2}-\frac {i \pi f g \,x^{2} \mathrm {csgn}\left (i c \left (e \,x^{2}+d \right )^{p}\right )^{3}}{2}+\frac {i \pi \,f^{2} \mathrm {csgn}\left (i c \right ) \mathrm {csgn}\left (i c \left (e \,x^{2}+d \right )^{p}\right )^{2} \ln \relax (x )}{2}+\frac {i \pi \,f^{2} \mathrm {csgn}\left (i \left (e \,x^{2}+d \right )^{p}\right ) \mathrm {csgn}\left (i c \left (e \,x^{2}+d \right )^{p}\right )^{2} \ln \relax (x )}{2}+\frac {i \pi \,g^{2} x^{4} \mathrm {csgn}\left (i c \right ) \mathrm {csgn}\left (i c \left (e \,x^{2}+d \right )^{p}\right )^{2}}{8}+\frac {i \pi \,g^{2} x^{4} \mathrm {csgn}\left (i \left (e \,x^{2}+d \right )^{p}\right ) \mathrm {csgn}\left (i c \left (e \,x^{2}+d \right )^{p}\right )^{2}}{8}-\frac {d^{2} g^{2} p \ln \left (e \,x^{2}+d \right )}{4 e^{2}}+\frac {d \,g^{2} p \,x^{2}}{4 e} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 1.30, size = 161, normalized size = 1.05 \[ \frac {1}{2} \, {\left (\log \left (e x^{2} + d\right ) \log \left (-\frac {e x^{2} + d}{d} + 1\right ) + {\rm Li}_2\left (\frac {e x^{2} + d}{d}\right )\right )} f^{2} p + f^{2} \log \relax (c) \log \relax (x) - \frac {{\left (e^{2} g^{2} p - 2 \, e^{2} g^{2} \log \relax (c)\right )} x^{4} + 2 \, {\left (4 \, e^{2} f g p - d e g^{2} p - 4 \, e^{2} f g \log \relax (c)\right )} x^{2} - 2 \, {\left (e^{2} g^{2} p x^{4} + 4 \, e^{2} f g p x^{2} + 4 \, d e f g p - d^{2} g^{2} p\right )} \log \left (e x^{2} + d\right )}{8 \, e^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {\ln \left (c\,{\left (e\,x^2+d\right )}^p\right )\,{\left (g\,x^2+f\right )}^2}{x} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (f + g x^{2}\right )^{2} \log {\left (c \left (d + e x^{2}\right )^{p} \right )}}{x}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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